What is the value of (A2-B2)2 if A=6 and B=5?

To find the value of (A^2 - B^2)^2 when A = 6 and B = 5, first, we need to calculate A^2 and B^2.

A^2 (6^2) is 36, and B^2 (5^2) is 25. Next, we subtract B^2 from A^2:

36 - 25 equals 11.

Now, we take this result and square it:

(11)^2 equals 121.

Therefore, the calculated value of (A^2 - B^2)^2 is 121, which matches the answer provided. This is why that answer is the correct choice for the question.